P=25x^2-3025

Solution for P=25x^2-3025 equation:

=25P^2-3025

We move all terms to the left:

-(25P^2-3025)=0

We get rid of parentheses

-25P^2+3025=0

a = -25; b = 0; c = +3025;
Δ = b2-4ac
Δ = 02-4·(-25)·3025
Δ = 302500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{302500}=550$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-550}{2*-25}=\frac{-550}{-50}
=+11
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+550}{2*-25}=\frac{550}{-50}
=-11
$